Given the following question:
[tex]area=2\pi r(h+r)[/tex][tex]\begin{gathered} a=2\pi r(h+r) \\ \text{Part B} \\ r=5 \\ h=23 \\ 2\times\pi\times5(23+5) \\ 23+5=28 \\ 2\times\pi\times5\times28 \\ 2\times\pi=6.28 \\ 6.28\times5\times28 \\ 5\times28=140 \\ 140\times6.28=879.2 \\ SA=879.2\text{ of shape b} \end{gathered}[/tex]