Given the equation
[tex]\text{ T=2 }\pi\sqrt[]{\frac{L}{g}}[/tex]
Given that g = 32 feet/sec and T = 1sec, we want to look for the value of L at this value
Substitute g=32 and T = 1 into the equation above
[tex]\begin{gathered} \text{ T=2 }\pi\sqrt[]{\frac{L}{g}} \\ 1\text{=2 }\pi\sqrt[]{\frac{L}{32}} \\ \text{divide both sides by 2 }\pi \\ \frac{1}{\text{2 }\pi}=\sqrt[]{\frac{L}{32}} \end{gathered}[/tex]
square both sides
[tex]\begin{gathered} (\frac{1}{\text{2 }\pi})^2=(\sqrt[]{\frac{L}{32}})^2 \\ \frac{1}{4\pi^2}=\frac{L}{32} \\ 4\pi^2L\text{ = 32} \\ L\text{ = }\frac{32}{4\pi^2} \\ L=0.81057\text{ foot} \end{gathered}[/tex]
But we are asked to leave the answer in inch, to achieve this, we will convert the 0.81057 feet to inch by multiplying by 12
L = 0.81057 x 12
L = 9.72684
L = 10 inch (to nearest inch)
The Length is 10 inches (to the nearest inch)