Question

Using 0.082 as your R value, what is the pressure in atm, of 0.25 mols of a gas at 300K in a 4L container?

Answer 1

Answer:

$\text{ }1.5375\text{ atm}$

Explanation:

Here, we want to get the value of the pressure in atm

Mathematically, we can use the ideal gas equation for this

This is calculated as follows:

$\begin{gathered} PV\text{ =nRT} \\ P\text{ = }\frac{nRT}{V} \end{gathered}$

where n is the number of moles which is given as 0.25

R is the molar gas constant which is 0.082

T is the temperature, given as 300K

V is the volume, given as 4L

Substituting these values, we have it that:

$P=\frac{0.25\times0.082\times300}{4}\text{ = }1.5375\text{ atm}$