Solution
Given
[tex]x^2+2x-2=0\text{ ----------\lparen1\rparen}[/tex]
Using the completing the square method
Adding 2 to both sides of equation 1.
[tex]\begin{gathered} x^2+2x-2+2=2 \\ \\ \Rightarrow x^2+2x=2 \end{gathered}[/tex]
Adding square of half of the coefficient of x to both sides
[tex]\begin{gathered} x^2+2x+(\frac{2}{2})^2=2+(\frac{2}{2})^2 \\ \\ \Rightarrow x^2+2x+1=2+1 \\ \\ \Rightarrow x^2+2x+1=3 \\ \\ \Rightarrow(x+1)^2=3 \end{gathered}[/tex]
Taking the square roots of both sides,
[tex]\begin{gathered} x+1=\pm\sqrt{3} \\ \\ \Rightarrow x=-1\pm\sqrt{3} \end{gathered}[/tex]