Question

Teaneck high had an enrollment of 11850 in 1983 and an enrollment of 11630 in year 1992. What is the predicted enrollment of Teaneck High in 2016 if we assume a linear model? Predicted enrollment = _______

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

enrollment:

1983 ===> 11850

1992 ===> 11630

Step 02:

linear model:

slope:

$m=\frac{y2-y1}{x2-x1}=\frac{11630-11850}{1992-1983}=\frac{-220}{9}=-24.44$

equation of the line:

point-slope form of the line

(y - y1) = m (x - x1)

(y - 11850) = - 24.44 (x - 1983)

y = - 24.44x + 48464.52 + 11850

y = -24.44x + 60314.52

if x = 2016:

y = -24.44(2016) + 60314.52

y = 11043.48

The answer is:

Predicted enrollment = 11043.48