Determine the equation of a least square line:
[tex]\bar{y}=a+b\bar{x}[/tex]
where b = slope,
[tex]S_x=5.36,S_y=15.35,\bar{x}=1.75,\bar{y}=9.07[/tex]
[tex]\begin{gathered} b=\frac{SS_{xy}}{SS_x} \\ SS_{xy}=\sqrt[]{(5.36)(15.35)}= \\ S_x=5.36 \\ b=\frac{9.06995}{5.36}=1.69 \end{gathered}[/tex][tex]\begin{gathered} a=y-bx \\ a=9.07-1.69(1.75) \\ a=9.07-2.9237 \\ a=6.1463 \end{gathered}[/tex]
Therefore the equation of the least square line:
[tex]\begin{gathered} \bar{y}=a+b\bar{x} \\ \bar{y}=6.15+1.69x \end{gathered}[/tex]
