Question

Assume you have a normal distribution with a mean of 75 and a standard deviation of 14. Find the Z-Score of 62, rounding your answer to the nearest HUNDREDTH.

Answer 1

STEP - BY - STEP EXPLANATION

What to find?

The z-score of 62

Given:

mean(μ) = 75

Standard deviation (σ) = 14

x- = 62

Step 1

Recall the formula for z - score.

$Z=\frac{x-\mu}{\sigma}$

Step 2

Substitute the values into the formula and simpl

$Z=\frac{62-75}{14}$

$\approx-0.93$

ANSWER

-0.93