Question

A box, initially at rest, has 23.4 N of force exerted on it for 2.56 s. If the box has a mass of 7.33 kg, what was its velocity at this time?

Answer 1

Given:

The force applied on the box, F=23.4 N

The time duration for which the force is applied, t=2.56 s

The initial velocity of the box, u=0 m/s

The mass of the box, m=7.33 kg

To find:

The velocity of the box.

Explanation:

From Newton's second law, the force applied to the box is given by,

$F=ma$

Where a is the acceleration of the box due to the applied force.

On substituting the known values,

$\begin{gathered} 23.4=7.33\times a \\ \Rightarrow a=\frac{23.4}{7.33} \\ =3.19\text{ m/s}^2 \end{gathered}$

From the equation of motion, the final velocity of the box is given by,

$v=u+at$

On substituting the known values,

$\begin{gathered} v=0+3.19\times2.56 \\ =8.17\text{ m/s} \end{gathered}$

Final answer:

The velocity of the box is 8.17 m/s