Question

Christy is twice as old as Renee. Angela is 4 years younger than Renee. If the sum of the sister's ages is 60, find the age of each sister.

Answer 1

Given:

Let, x denote the age of Renee.

Christy is twice as old as Renee = 2x

Angela is 4 years younger than Renee = x-4

The sum of the sister's ages is 60.

The equation is given as,

$2x+(x-4)+x=60$

Solve the equation,

$\begin{gathered} 2x+(x-4)+x=60 \\ 4x=60+4 \\ 4x=64 \\ x=16 \\ \text{ Rene}e=x=16\text{ years} \\ \text{Christy}=2x=2\cdot16=32\text{ years} \\ \text{Angela}=x-4=16-4=12\text{ years} \end{gathered}$

Answer:

$\begin{gathered} 2x+(x-4)+x=60 \\ \text{ Rene}e=16\text{ years} \\ \text{Christy}=32\text{ years} \\ \text{Angela}=12\text{ years} \end{gathered}$