Question

If the object is at rest what is the net force acting on it?

Answer 1

We will have the following:

First, we remember:

$\begin{cases}F=-kx \\ \\ F=mg \\ \\ -kx=mg\end{cases}$

So, the net force will be:

$F=(0.005\operatorname{kg})(9.8m/s^2)\Rightarrow F=0.049N$

So, the net force would be 0.049 N.

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