There is a relation between current, voltage and number of turns in a transformer
[tex]Constant=\frac{V_1}{V_2}=\frac{n_1}{n_2}=\frac{I_2}{I1}[/tex]We have the number of turns for both coils and the voltage on the primary. with this we can get the voltage on the second coil
[tex]\begin{gathered} \frac{24V}{V_2}=\frac{25}{200} \\ \\ V_2=192V \end{gathered}[/tex]With this voltage we can get the current by using the next formula:
[tex]\begin{gathered} V=IR \\ \\ 192V=I\cdot20\Omega \\ I=9.6A \end{gathered}[/tex]Answer: I=9.6A