After the ball was caught, what was the Kinetic energy ?What was the kinetic energy converted into? previous info:P.E = 60J before it was caughtK.E = 75 J before it was caught

Kinetic energy after the ball was caught = 0 J
The kinetic energy was converted into potential energy
Explanation:The ball was caught when the ball was at maximum height
Note that:
At maximum height, velocity, v = 0 m/s
The kinetic energy is given by the formula:
[tex]KE=\frac{1}{2}mv^2[/tex]Substitute m = 1.5 kg and v = 0 m/s into the formula
[tex]\begin{gathered} KE=\frac{1}{2}\times1.5\times0^2 \\ \\ KE=0J \end{gathered}[/tex]