Question

At 11:05 a.m. a man in a parachute is 8000 feet above the ground. At 11:08 a.m. the same man is 5400 feet above the ground What is the average rate of change, in feet per minute, between 11:05 a.m. and 11:08 a.m.? a 3 2600 2600 3 2600 3 3 d 2600

Answer 1

The average rate of change in feet per minute is given as:

$\text{Rate}=\frac{Change\text{ in distance above the ground}}{\text{Change in time}}$$R=\frac{(5400-8000)\text{feet}}{(11\colon08-11\colon05)\text{minute}}$$R=-\frac{2600}{3}$

Hence, the average rate of change is -2600/3, Option B