Given that the mass of the ball, m = 5 kg
The initial velocity of the ball is
[tex]V_o=6\text{ m/s}[/tex]
The final velocity of the ball is
[tex]V_f=4\text{ m/s}[/tex]
We have to find the work done.
The work done can be calculated by the formula,
[tex]\begin{gathered} W=\text{ change in kinetic energy} \\ =\frac{1}{2}m(V_f)^2-\frac{1}{2}m(V_o)^2 \end{gathered}[/tex]
Substituting the values, the work done will be
[tex]\begin{gathered} W=\frac{1}{2}\times5\times(4)^2-\frac{1}{2}\times5\times(6)^2 \\ =40-90 \\ =-50\text{ J} \end{gathered}[/tex]
Thus, the work done will be -50 J
