Question

Write the slop e intercept form of the equation of the line through the giren point with the girenslope.9) through: (-1,3), slope =-510) through: (-2,-3), slope =-111) through: (-5, 3), slope ---12) through: (2, 1), slope = 1Write the slope-intercept form of the equation of the line through the given points13) through: (5, 3) and (5, 4)14) through: (0, 4) and (2, 3)15) trough: (-1, 4) and (-4,-5)16) through: (-1, -2) and (-3,0)

Answer 1

In this case the answer is very simple.

To find the solution to the exercise we'll have to carry out several steps.

Step 01:

Data

slope = m = - 1 / 7

point (-5 , 3 ) x1 = -5 y1 = 3

Step 02:

Point-Slope Form of a Straight Line

$(y\text{ - y1) = m (x - 1)}$$(y\text{ - 3) = }\frac{-1}{7}\cdot(x-(-5))$$\begin{gathered} (y\text{ -3) = }\frac{-1}{7}(x\text{ +5)} \\ (y-3)\text{ = }\frac{-x}{7}\text{ -}\frac{5}{7}\text{ } \\ y\text{ = }\frac{-x}{7}\text{ -}\frac{5}{7}+3 \end{gathered}$$\begin{gathered} y\text{ = }\frac{-x}{7}-\frac{5+21}{7} \\ y\text{ = }\frac{-x}{7}\text{ }+\frac{16}{7} \end{gathered}$

The answer is :

$y\text{ = }\frac{-x}{7}+\frac{16}{7}$