Question

What is the frequency (s-1) of a photon that has an energy of 4.38 × 10-18 J?

Answer 1

Answer

6.61 x 10¹⁵ s⁻¹

Procedure

Calculate the frequency of the photon emitted using the formula

$f=\frac{E}{h}$

Where E is the energy 4.38 × 10-18 J and h is the plank's constant 6.6261 × 10-34 J/s

$f=\frac{4.38\text{ }\times10^{-18}\text{ J s}^{-1}}{6.6261\times10^{-34}J}=6.610\times10^{15}s^{-1}$