The volume of a sphere is calculated as follows:
[tex]V=\frac{4}{3}\pi r^3[/tex]
where r is the radius of the sphere.
Substituting with r = 5 cm, we get:
[tex]\begin{gathered} V=\frac{4}{3}\cdot\pi\cdot5^3 \\ V=\frac{4}{3}\cdot\pi\cdot125 \\ V=523.3\operatorname{cm}^3 \end{gathered}[/tex]
The volume of a right circular cone is calculated as follows:
[tex]V=\pi r^2\frac{h}{3}[/tex]
where h is the height of the cone.
Substituting with r = 5 cm, and h = 11 cm, we get:
[tex]\begin{gathered} V=\pi\cdot5^2\cdot\frac{11}{3} \\ V=\pi\cdot25\cdot\frac{11}{3} \\ V=287.8\operatorname{cm}^3 \end{gathered}[/tex]
The volume of the cone is less than the volume of the sphere, then the
entire volume of the frozen yogurt cannot fit completely inside the
cone.