Respuesta :

The sides IF and HG are parallel, so we have a trapezoid IHGF.

Since the sides IH and FG have the same length, we have an isosceles trapezoid.

That means the angles ∠I and ∠F are congruent, so the angle ∠F is equal 35°.

Since the figure is a trapezoid, the angles ∠F and ∠G are supplementary (because they are consecutive interior angles), so we have:

[tex]\begin{gathered} \angle F+\angle G=180 \\ 35+\angle G=180 \\ \angle G=180-35 \\ \angle G=145\degree \end{gathered}[/tex]

So the angle ∠G is equal to 145°.

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