Question

Find the equation of the perpendicular bisector of the line AB with A(-27) and B(5,2)

Answer 1

$\begin{gathered} m=\frac{7-2}{-2-5}=\frac{5}{-7} \\ m_T=\frac{1}{-m}=\frac{7}{5} \end{gathered}$

With the perpendicular slope, we can find the line function

$\begin{gathered} y=m_Tx+b \\ 2=\frac{7}{5}\cdot5+b \\ 2-7=b=-5 \\ y=\frac{7}{5}x-5 \end{gathered}$