Question

d^2-9d+20=0 solve by factoring

Answer 1

ANSWER:

$\begin{gathered} d_1=4 \\ d_2=5 \end{gathered}$

STEP-BY-STEP EXPLANATION:

We have the following expression

$d^2-9d+20=0$

Solving fir factoring:

$\begin{gathered} d^2-4d-5d+20=0 \\ d(d-4)-5(d-4)=0 \\ (d-4)\cdot(d-5)=0 \\ d-4=0\rightarrow d_1=4 \\ d-5=0\rightarrow d_2=5 \end{gathered}$