Answer:
[tex]A(t)=A_0e^{-0.0315t}[/tex]Explanation:
The exponential decay model has the form
[tex]A(t)=A_0e^{-kt}[/tex]Where A0 is the initial amount of Pb-210 and k is equal to
[tex]k=\frac{\ln2}{T}[/tex]Where T is the half-life. Replacing T = 22 years, we get
[tex]k=\frac{\ln2}{22}=0.0315[/tex]Therefore, the exponential decay model is
[tex]A(t)=A_0e^{-0.0315t}[/tex]