Question

(b) 76athletes are running a race. A gold medal is to be given to the winner, a silver medal is to begiven to the second-place finisher, and a bronze medal is to be given to the third-place finisher.Assume that thereare no ties. In how0how many possible ways can the 3 medals be distributed?

Answer 1

Given:

Total athletes = 76

We have to choose 1 gold medal winner, 1 silver medal winner and 1 bronze medal winner. That is, to select 3 out of 76 athletes. Therefore, we have:

$76P3=\frac{76!}{(76-3)!}$

Simplify:

$=\frac{76!}{73!}=\frac{76\times75\times74\times73!}{73!}=421800$

Answer: 421800 ways