Given that:
- A sample of children taken was:
[tex]n=686[/tex]
- The sample mean is:
[tex]\bar{x}=6.8[/tex]
- The population standard deviation is:
[tex]\sigma=2.1[/tex]
You know that you must construct the 85% confidence interval for the mean number of toys purchased each year.
Then, you need to use the Confidence Interval Formula for the Mean:
[tex]\bar{x}\pm z\cdot\frac{\sigma}{\sqrt{n}}[/tex]
Where "z" is the critical value for confidence level, "n" is the sample size, σ is the standard deviation, and this is the sample mean:
[tex]\bar{x}[/tex]
By definition the value of "z" for an 85% confidence interval is:
[tex]z=1.44[/tex]
Therefore, by substituting values into the formula and evaluating, you get:
[tex]6.8\pm1.44\cdot\frac{2.1}{\sqrt{686}}[/tex][tex]Lower\text{ }endpoint\rightarrow6.8-1.44\cdot\frac{2.1}{\sqrt{686}}\approx6.7[/tex][tex]Upper\text{ }endpoint\rightarrow6.8+1.44\cdot\frac{2.1}{\sqrt{686}}\approx6.9[/tex]
Hence, the answer is:
[tex]Lower\text{ }endpoint:6.7[/tex][tex]Upper\text{ }endpoint:6.9[/tex]