Juan deposited $4000 into an amount with 3.6% interest, compounded monthly. Assuming that no withdrawal are made, how much will he have in the account after 9 years? Round up to the nearest cent

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Compound Interest

The final value of an investment of P dollars at an APR of r for t years is given by:

[tex]FV=P\mleft(1+\frac{r}{m}\mright)^{m\cdot t}[/tex]

Where m is the number of compounding periods per year.

Juan deposited P = $4,000 into an account at r = 3.6% compounded monthly. Since there are 12 months in a year, m = 12.

Substituting for t = 9 years:

[tex]FV=\$4,000\mleft(1+\frac{0.036}{12}\mright)^{12\cdot9}[/tex]

Calculating:

[tex]\begin{gathered} FV=\$4,000(1+0.003)^{108} \\ FV=\$4,000(1.003)^{108} \\ FV=\$4,000\cdot1.381977 \\ FV=\$5,527.91 \end{gathered}[/tex]

Juan will have $5,527.91 in the account

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