Question

If you have 9.4 x 10^24 molecules of gold how many grams of gold do you have?

Answer 1

Answer:

3,075.61 grams

Explanations:

According to the Avogadro's constant;

$1\text{mole}=6.02\times10^{23}molecules$

Convert the molecules of Gold to mole using the conversion factor:

$\begin{gathered} \text{moles of Au=}\frac{9.4\times10^{24}}{6.02\times10^{23}} \\ \text{moles of Au=}1.56\times10^{24-23} \\ \text{moles of Au=}1.56\times10 \\ \text{moles of Au=}15.6\text{moles} \end{gathered}$

Determine the mass of Gold

$\begin{gathered} \text{Mass}=\text{mole}\times\text{molar mass} \\ \text{Mass}=15.6\cancel{\text{moles}}\times\frac{196.97g}{\cancel{\text{mol}}} \\ \text{Mass}=3,075.61\text{grams} \end{gathered}$

Hence the mass of Gold is 3,075.61 grams