Answer;
5(2+ 11b)
Explanation:
The distributive property allows us to says that for example
[tex]5(4+1)=5\cdot4+5\cdot1[/tex][tex]10a+55b[/tex]now we can write 10 = 2 * 5 and 55 = 11 * 5 and so we can write
[tex]\begin{gathered} 10a+55b \\ 2\cdot5a+11\cdot5b \end{gathered}[/tex]we can factor out the 5 to get
[tex]5(2a+11b)[/tex]which is our answer!