Answer:
for t = 1: x = 1/2, y= 0
for t = 2: x = 2/3, y = -1
Explanation:
To fill the table, we just evaluate x and y at the given values of t.
For t = 1, we have
[tex]x=\frac{t}{t+1}\rightarrow\frac{1}{1+1}=\frac{1}{2}[/tex][tex]\boxed{x=\frac{1}{2}.}[/tex]
And
[tex]y=1-t\rightarrow1-1=0[/tex][tex]\boxed{y=0.}[/tex]
For t = 2, the value of x becomes
[tex]x=\frac{t}{t+1}\rightarrow\frac{2}{2+1}[/tex][tex]\rightarrow\boxed{x=\frac{2}{3}.}[/tex]
The value of y becomes
[tex]y=1-2[/tex][tex]undefined[/tex]
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