Respuesta :

we have the triangle TUV

we know H, E and D are midpoints, and as you call from the previous one, the midsegment is made by the midpoints, so HE is the midsegment of the triangle, with a parallel base of UV, well, we know what UV is, so the midsegment is half that.

UV=68

TV=88

HD=68

[tex]HE=\frac{68}{2}=34[/tex]

HE=34

Ver imagen ErialO69989
ACCESS MORE
EDU ACCESS
Universidad de Mexico