We have :
[tex]\begin{gathered} x\text{ and }x+7km/h\text{ } \\ \\ 5hours(x+x+7km/h)=265 \\ 5(2x+7)=265 \\ 2x+7=\frac{265}{5} \\ \\ 2x=53\text{ - 7} \\ x=\frac{46}{2}=23km/h\text{ } \\ \\ The\text{ other one is= 23 + 7 = }30km/h \end{gathered}[/tex]23 and 30 km/h