Given:
[tex]3\times2\begin{bmatrix}{-2} & {3} & {0} \\ {-4} & {2} & {6} \\ {6} & {-5} & {6}\end{bmatrix}[/tex]
Simplify,
[tex]\begin{gathered} 3\times2\begin{bmatrix}{-2} & {3} & {0} \\ {-4} & {2} & {6} \\ {6} & {-5} & {6}\end{bmatrix}=6\begin{bmatrix}{-2} & {3} & {0} \\ {-4} & {2} & {6} \\ {6} & {-5} & {6}\end{bmatrix} \\ =\begin{bmatrix}{-2\cdot6} & {3\cdot6} & {0\cdot6} \\ {-4\cdot6} & {2\cdot6} & {6\cdot6} \\ {6\cdot6} & {-5\cdot6} & {6\cdot6}\end{bmatrix}\ldots\text{ By applying scalar multiplication} \\ =\begin{bmatrix}{-12} & {18} & {0} \\ {-24} & {12} & {36} \\ {36} & {-30} & {36}\end{bmatrix} \end{gathered}[/tex]
Answer: option B)
[tex]\begin{bmatrix}{-12} & {18} & {0} \\ {-24} & {12} & {36} \\ {36} & {-30} & {36}\end{bmatrix}[/tex]
