we have the following ratio:
[tex]\frac{ZINC}{COOPER}=\frac{4}{17}[/tex]Now, we know that there are 578 gr of cooper. By substituting this values into our ratio, we have
[tex]\frac{ZINC}{578}=\frac{4}{17}[/tex]and we must isolate ZINC. This can be done by moving 578 to the right hand side:
[tex]\begin{gathered} \text{ZINC}=578\cdot\frac{4}{17} \\ \text{ZINC}=\frac{578\cdot4}{17} \\ \text{ZINC}=\frac{2312}{17} \\ \text{ZINC =136} \end{gathered}[/tex]that is, the jar contains 136 gr of zinc