The tangent of one of the acute angles of a right triangle is defined as the ratio between the side across the angle (opposite) and the side next to the angle (adjacent)
[tex]\tan \theta=\frac{\text{opposite}}{\text{adjacent}}[/tex]Considering ∠N, the side next to it is side NA, and the side across the angle is DA.
So you can express the tangent of ∠N as follows:
[tex]\tan N=\frac{DA}{NA}[/tex]We know that DA=16 and NA=12, then the tangent can be calculated as:
[tex]\begin{gathered} \tan N=\frac{16}{12} \\ \tan N=\frac{4}{3} \end{gathered}[/tex]The tangent of ∠N is 4/3
