ANSWER
B. 4 and 6
EXPLANATION
The function is partially factored. As we can see, one of the factors is (x - 4), which means that x = 4 is one of the three zeros this function has.
The other two zeros are the zeros of the factor (x² - 12x + 36), so we have to solve,
[tex]x^2-12x+36=0[/tex]
To solve it, we can use the quadratic formula,
[tex]\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \end{gathered}[/tex]
In this case, a = 1, b = -12, and c = 36,
[tex]x=\frac{-(-12)\pm\sqrt{(-12)^2-4\cdot1\cdot36}}{2\cdot1}=\frac{12\pm\sqrt{144-144}}{2}=\frac{12\pm0}{2}=\frac{12}{2}=6[/tex]
We should have got two zeros, but we only got one since the discriminant is 0. This means that this zero has multiplicity 2.
Hence, the zeros of this function are 4 and 6.
