Question

Help I’m completely lost on this one. I have no idea what I’m doing

Answer 1

$3\frac{y^{}}{x^2}-5\frac{z}{x^3y}$

Explanation

Step 1

$\frac{9x^2y^5-15xy^3z}{3x^4y^4}$

Step 1

split the fraction

$\frac{9x^2y^5-15xy^3z}{3x^4y^4}=\frac{9x^2y^5}{3x^4y^4}-\frac{15xy^3z}{3x^4y^4}$

Step 2

make the division by subtracting the exponents

$\begin{gathered} \frac{9x^2y^5}{3x^4y^4}-\frac{15xy^3z}{3x^4y^4} \\ \frac{9^{}y^{}}{3x^2}-\frac{15^{}z}{3x^3y^{}} \\ 3\frac{y^{}}{x^2}-5\frac{z}{x^3y} \end{gathered}$