Previously calculated area in part A is
[tex]20\frac{2}{3}units^2[/tex]5/6th of the given value is calculated as,
[tex]\text{Required area = }\frac{5}{6}\text{ }\times\text{ 20}\frac{2}{3}[/tex]Simplifying further,
[tex]\begin{gathered} \text{Required area =}\frac{5}{6}\text{ }\times\text{ }\frac{62}{3} \\ \text{Required area = }\frac{5\times62}{6\times3} \\ \text{Required area = }\frac{310}{18} \\ \text{Required area = 17}\frac{4}{18}units^2 \end{gathered}[/tex]Thus the required area is,
[tex]\text{ 17}\frac{4}{18}units^2[/tex]