For this case we need to remember the definition of a line given by this formula:
[tex]y=mx+b[/tex]And we have the following points given: (2,3) and (5,8)
And we can find the slope with the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{8-3}{5-2}=\frac{5}{3}[/tex]And using one point we got:
[tex]3=\frac{5}{3}(2)+b[/tex]And solving for b we got:
[tex]b=3-\frac{10}{3}=-\frac{1}{3}[/tex]And our equation would be:
[tex]y=\frac{5}{3}x-\frac{1}{3}[/tex]