Question

Find the missing length of the longer leg in each 30-60-90 triangle. Leave the answer in racial form: short leg = 9

Answer 1

Find the missing length of the longer leg in each 30-60-90 triangle. Leave the answer in racial form: short leg = 9​

we know that

$\sin (60^o)=\frac{\sqrt[\square]{3}}{2}$$\cos (60^o)=\frac{1}{2}$$\tan (60^o)=\sqrt[\square]{3}$

so

In this problem

$\tan (60^o)=\frac{\text{long leg}}{\text{short leg}}$

substitute the given values

$\begin{gathered} \sqrt[\square]{3}=\frac{\text{long leg}}{\text{9}} \\ \\ \text{long leg=9}\sqrt[\square]{3} \end{gathered}$