Let:
A = Length of the large sandwich = 11/12 ft
B = Length of the small sandwich
so:
[tex]\begin{gathered} B=\frac{3}{4}\cdot A \\ so\colon \\ B=\frac{3}{4}\cdot\frac{11}{12} \\ B=\frac{11}{16}ft \end{gathered}[/tex]Answer:
11/16 ft or as a decimal 0.6875 ft