Respuesta :

Given

points which lie on the function (1,1),(2,7),(3,19)

Find

the quadratic function

Explanation

(1,1) will lie on the function

So,

[tex]\begin{gathered} a(1)^2+b(1)+c=1 \\ a+b+c=1\text{ ----------\lparen1\rparen} \end{gathered}[/tex]

(2,7) will lie on the function

[tex]\begin{gathered} a(2)^2+b(2)+c=7 \\ 4a+2b+c=7\text{ ------------\lparen2\rparen} \end{gathered}[/tex]

(3,19) will lie on the function

[tex]\begin{gathered} a(3)^2+b(3)+c=19 \\ 9a+3b+c=19----------(3) \end{gathered}[/tex]

Solving all these equations

We get a =3, b=-3 and c=1

Final Answer

[tex]f(x)=y=3x^2-3x+1[/tex]

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