Given
points which lie on the function (1,1),(2,7),(3,19)
Find
the quadratic function
Explanation
(1,1) will lie on the function
So,
[tex]\begin{gathered} a(1)^2+b(1)+c=1 \\ a+b+c=1\text{ ----------\lparen1\rparen} \end{gathered}[/tex](2,7) will lie on the function
[tex]\begin{gathered} a(2)^2+b(2)+c=7 \\ 4a+2b+c=7\text{ ------------\lparen2\rparen} \end{gathered}[/tex](3,19) will lie on the function
[tex]\begin{gathered} a(3)^2+b(3)+c=19 \\ 9a+3b+c=19----------(3) \end{gathered}[/tex]Solving all these equations
We get a =3, b=-3 and c=1
Final Answer
[tex]f(x)=y=3x^2-3x+1[/tex]