Question

a jar contains 23 blue 6 black and 24 yellow marbles a marble is drawn at random p( yellow or blue)

Answer 1

Solution:

Given;

$n(blue)=23,n(black)=6,n(yellow)=24,n(total)=53$

Thu;

$\begin{gathered} P(yellow\text{ or }blue)=P(yellow)+P(blue) \\ \\ P(yellow\text{ or }blue)=\frac{24}{53}+\frac{23}{53} \\ \\ P(yellow\text{ or }blue)=\frac{47}{53} \end{gathered}$

ANSWER:

$\frac{47}{53}$