Respuesta :

Define the variables involved in the situation, which are x and y.

According to the statement, the sum of x and y is 15, this is:

[tex]x+y=15[/tex]

It is also said that 3 times one number, this is 3x, is 11 less than 5 times the other, this is 5y-11.

[tex]3x=5y-11[/tex]

Solve the system formed by these equations:

[tex]\begin{gathered} x+y=15 \\ 3x=5y-11 \end{gathered}[/tex]

Use equalization method to solve the system, to do this, solve both equations for one of the variables and then make them equal:

[tex]\begin{gathered} x=15-y \\ x=\frac{(5y-11)}{3} \\ 15-y=\frac{(5y-11)}{3} \\ 45-3y=5y-11 \\ 45+11=5y+3y \\ 56=8y \\ \frac{56}{8}=y \\ y=7 \end{gathered}[/tex]

y has a value of 7. Use this value and one of the equations above to find the value of x:

[tex]\begin{gathered} x+y=15 \\ x+7=15 \\ x=15-7 \\ x=8 \end{gathered}[/tex]

x has a value of 8.

The numbers are 7 and 8.

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