[tex]\begin{gathered} \text{This problem is a direct proportion problem} \\ so\text{ that Time(min) }\propto\text{ Total distance travelled(ft)} \end{gathered}[/tex][tex]\begin{gathered} t=kd \\ t\text{ =4} \\ d=24 \\ 4\text{ = 24k} \\ k\text{ = }\frac{4}{24}=\frac{1}{6} \\ t\text{ = }\frac{1}{6}d \end{gathered}[/tex]
Now we have the constant of proportionality, we can fill the table in (1)
if t=6,
6 = 1/6 x d
d = 36 ft
if d = 60 ft
t = 1/6 x 60
t = 10 mins
If d =18 ft
t = 1/6 x 18
t = 3 mins
If t = 1
1= 1/6 x d
d = 6 ft
Now let me draw the table and insert the values we just got