[tex]\begin{gathered} you\text{ must choose 2 points of the given line, for example} \\ (x_1,y_1)=(0,-3)and(x_2,y_2)=(-3,-1) \\ \text{and compute the slope} \\ m=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex][tex]\begin{gathered} by\text{ substituying those points in m, one has} \\ m=\frac{-1-(-3)}{-3-0} \\ m=\frac{-1+3}{-3} \\ m=\frac{2}{-3} \\ m=-\frac{2}{3} \end{gathered}[/tex][tex]\begin{gathered} \sin ce\text{ the unknow line must be parallel, it must have the same slope. Hence, } \\ y=-\frac{2}{3}x+b \\ \text{and b can be solved with the information that, the lines passes throgh (-3,3), then} \\ 3=-\frac{2}{3}(-3)+b \\ 3=\frac{2\cdot3}{3}+b \\ 3=2+b \\ 3-2=b \\ 1=b\Rightarrow b=1 \\ \text{The solution is} \\ y=-\frac{2}{3}x+1 \end{gathered}[/tex]
