Solution
We have the following function given:
[tex]f(x)=(x+2)^2-5[/tex]And we want to find the inverse so then we can apply this procedure:
1) Replace x by y:
[tex]x=(y+2)^2-5[/tex]2) Solve for y and we got:
[tex]x+5=(y+2)^2[/tex]Taking the square root and we got:
[tex]y+2=\sqrt[]{x+5}[/tex]And we got:
[tex]y=\pm\sqrt[]{x+5}-2[/tex]