Question

5. __K + __P2 --> __K3P

Answer 1

Answer:

$6K+P_2\operatorname{\rightarrow}2K_3P.$

Applying the trial and error method: If we balance P first, we put '2' moles beside K3P, so P is balanced on both sides:

$K+P_2\rightarrow2K_3P.$

But K is still unbalanced and now, we have 6 K because 2 x 3 = 6. If we put '6' moles beside K, we will obtain the balanced chemical equation:

$6K+P_2\operatorname{\rightarrow}2K_3P.$