Question

Use the equation: …..c. Give the location of any horizontal asymptote(s). If there is none, write “n/a.”(I only need help with question C)

Answer 1

Given

$\begin{gathered} h(x)=\frac{x+7}{x^2-49} \\ \end{gathered}$

Simplify

$\begin{gathered} h(x)=\frac{x+7}{x^2-49} \\ \\ h(x)=\frac{x+7}{(x^{}-7)(x+7)}=\frac{1}{(x^{}-7} \end{gathered}$

The degree of the numerator =0

The degree of the denominator =1

Since, the degree of the denominator is > the degree of the numerator

The horizontal asymptote is the x-axis

Therefore, The horizontal asymptote is; y = 0