Given a right triangle with the side lengths of legs = 9 and 13
For the required angle :
opposite side = 9
adjacent side = 13
so,
[tex]\begin{gathered} \tan \theta=\frac{opposite}{adjacent}=\frac{9}{13} \\ \\ \theta=\tan ^{-1}\frac{9}{13}=34.7 \end{gathered}[/tex]
