y = 10x - 7 ......eqn(1)
y = 8x - 5 ........eqn(2)
Equating both equations (1) and (2), we get,
10x - 7 = 8x - 5
10x - 8x = 7 - 5
2x = 2
Dividing both sides by 2, we get,
x = 2/2
x = 1
Substituting 1 for x in eqn(1), we get,
y = 10(1) - 7
y = 10 - 7
y = 3
Solution: x = 1, y = 3 or ( 1, 3 )
