Question

What volume of a 3.00M KI stock solution would you use to make 0.300 L of a 1.25M KI solution?

Answer 1

Answer:

0.125L

Explanations:

According to the dilution formula

$C_1V_1=C_2V_2$

where:

• C1 and C2 are the ,concentrations

,

• V1 and V2 are the, volumes

Given the following parameters

$\begin{gathered} C_1=3.00M \\ C_2=1.25M \\ V_2=0.300L \end{gathered}$

Requuired

Iniital volume V1

Substitute

$\begin{gathered} V_1=\frac{C_2V_2}{C_1} \\ V_1=\frac{1.25\times0.3}{3.0} \\ V_1=0.125L \end{gathered}$

Therefore the amount of volume required is 0.125L