Question

A man pushes a lawn mower on a level lawn with a force of 192 N. If 28% of this force is directed forward, how much work is done by the man in pushing the mower 7.2 m? answer with:___J

Answer 1

Given:

The man pushes the lawn mower with the force of

$F=192\text{ N}$

The forward-directed force is,

$28\text{ \%}$

The mower moves

$d=7.2\text{ m}$

To find:

The work done by the man

Explanation:

The force in the forward direction is,

$\begin{gathered} F^{\prime}=F\times28\text{ \%} \\ =192\times\frac{28}{100}\text{ N} \\ =53.8\text{ N} \end{gathered}$

The work in moving the lawn mower is,

$\begin{gathered} W=F^{\prime}d \\ =53.8\times7.2 \\ =387.4\text{ J} \end{gathered}$

Hence, the work done by the man in pushing the mower 7.2 m is 387.4 N.